Integrand size = 21, antiderivative size = 66 \[ \int \frac {\tan ^2(c+d x)}{a+b \tan (c+d x)} \, dx=-\frac {a x}{a^2+b^2}-\frac {\log (\cos (c+d x))}{b d}+\frac {a^2 \log (a \cos (c+d x)+b \sin (c+d x))}{b \left (a^2+b^2\right ) d} \]
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Time = 0.13 (sec) , antiderivative size = 77, normalized size of antiderivative = 1.17, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.190, Rules used = {3622, 3556, 3565, 3611} \[ \int \frac {\tan ^2(c+d x)}{a+b \tan (c+d x)} \, dx=\frac {a^2 \log (a \cos (c+d x)+b \sin (c+d x))}{b d \left (a^2+b^2\right )}+\frac {a^3 x}{b^2 \left (a^2+b^2\right )}-\frac {a x}{b^2}-\frac {\log (\cos (c+d x))}{b d} \]
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Rule 3556
Rule 3565
Rule 3611
Rule 3622
Rubi steps \begin{align*} \text {integral}& = -\frac {a x}{b^2}+\frac {a^2 \int \frac {1}{a+b \tan (c+d x)} \, dx}{b^2}+\frac {\int \tan (c+d x) \, dx}{b} \\ & = -\frac {a x}{b^2}+\frac {a^3 x}{b^2 \left (a^2+b^2\right )}-\frac {\log (\cos (c+d x))}{b d}+\frac {a^2 \int \frac {b-a \tan (c+d x)}{a+b \tan (c+d x)} \, dx}{b \left (a^2+b^2\right )} \\ & = -\frac {a x}{b^2}+\frac {a^3 x}{b^2 \left (a^2+b^2\right )}-\frac {\log (\cos (c+d x))}{b d}+\frac {a^2 \log (a \cos (c+d x)+b \sin (c+d x))}{b \left (a^2+b^2\right ) d} \\ \end{align*}
Result contains complex when optimal does not.
Time = 0.09 (sec) , antiderivative size = 78, normalized size of antiderivative = 1.18 \[ \int \frac {\tan ^2(c+d x)}{a+b \tan (c+d x)} \, dx=\frac {b (i a+b) \log (i-\tan (c+d x))+b (-i a+b) \log (i+\tan (c+d x))+2 a^2 \log (a+b \tan (c+d x))}{2 b \left (a^2+b^2\right ) d} \]
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Time = 0.29 (sec) , antiderivative size = 56, normalized size of antiderivative = 0.85
method | result | size |
parallelrisch | \(\frac {-2 a b d x +\ln \left (1+\tan ^{2}\left (d x +c \right )\right ) b^{2}+2 a^{2} \ln \left (a +b \tan \left (d x +c \right )\right )}{2 b d \left (a^{2}+b^{2}\right )}\) | \(56\) |
derivativedivides | \(\frac {\frac {\frac {b \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2}-a \arctan \left (\tan \left (d x +c \right )\right )}{a^{2}+b^{2}}+\frac {a^{2} \ln \left (a +b \tan \left (d x +c \right )\right )}{\left (a^{2}+b^{2}\right ) b}}{d}\) | \(68\) |
default | \(\frac {\frac {\frac {b \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2}-a \arctan \left (\tan \left (d x +c \right )\right )}{a^{2}+b^{2}}+\frac {a^{2} \ln \left (a +b \tan \left (d x +c \right )\right )}{\left (a^{2}+b^{2}\right ) b}}{d}\) | \(68\) |
norman | \(-\frac {a x}{a^{2}+b^{2}}+\frac {a^{2} \ln \left (a +b \tan \left (d x +c \right )\right )}{b d \left (a^{2}+b^{2}\right )}+\frac {b \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2 d \left (a^{2}+b^{2}\right )}\) | \(71\) |
risch | \(\frac {x}{i b -a}+\frac {2 i x}{b}+\frac {2 i c}{b d}-\frac {2 i a^{2} x}{b \left (a^{2}+b^{2}\right )}-\frac {2 i a^{2} c}{b d \left (a^{2}+b^{2}\right )}-\frac {\ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )}{b d}+\frac {a^{2} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-\frac {i b +a}{i b -a}\right )}{b d \left (a^{2}+b^{2}\right )}\) | \(140\) |
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Time = 0.25 (sec) , antiderivative size = 89, normalized size of antiderivative = 1.35 \[ \int \frac {\tan ^2(c+d x)}{a+b \tan (c+d x)} \, dx=-\frac {2 \, a b d x - a^{2} \log \left (\frac {b^{2} \tan \left (d x + c\right )^{2} + 2 \, a b \tan \left (d x + c\right ) + a^{2}}{\tan \left (d x + c\right )^{2} + 1}\right ) + {\left (a^{2} + b^{2}\right )} \log \left (\frac {1}{\tan \left (d x + c\right )^{2} + 1}\right )}{2 \, {\left (a^{2} b + b^{3}\right )} d} \]
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Result contains complex when optimal does not.
Time = 0.49 (sec) , antiderivative size = 405, normalized size of antiderivative = 6.14 \[ \int \frac {\tan ^2(c+d x)}{a+b \tan (c+d x)} \, dx=\begin {cases} \tilde {\infty } x \tan {\left (c \right )} & \text {for}\: a = 0 \wedge b = 0 \wedge d = 0 \\\frac {- x + \frac {\tan {\left (c + d x \right )}}{d}}{a} & \text {for}\: b = 0 \\\frac {i d x \tan {\left (c + d x \right )}}{2 b d \tan {\left (c + d x \right )} - 2 i b d} + \frac {d x}{2 b d \tan {\left (c + d x \right )} - 2 i b d} + \frac {\log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )} \tan {\left (c + d x \right )}}{2 b d \tan {\left (c + d x \right )} - 2 i b d} - \frac {i \log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{2 b d \tan {\left (c + d x \right )} - 2 i b d} - \frac {i}{2 b d \tan {\left (c + d x \right )} - 2 i b d} & \text {for}\: a = - i b \\- \frac {i d x \tan {\left (c + d x \right )}}{2 b d \tan {\left (c + d x \right )} + 2 i b d} + \frac {d x}{2 b d \tan {\left (c + d x \right )} + 2 i b d} + \frac {\log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )} \tan {\left (c + d x \right )}}{2 b d \tan {\left (c + d x \right )} + 2 i b d} + \frac {i \log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{2 b d \tan {\left (c + d x \right )} + 2 i b d} + \frac {i}{2 b d \tan {\left (c + d x \right )} + 2 i b d} & \text {for}\: a = i b \\\frac {x \tan ^{2}{\left (c \right )}}{a + b \tan {\left (c \right )}} & \text {for}\: d = 0 \\\frac {2 a^{2} \log {\left (\frac {a}{b} + \tan {\left (c + d x \right )} \right )}}{2 a^{2} b d + 2 b^{3} d} - \frac {2 a b d x}{2 a^{2} b d + 2 b^{3} d} + \frac {b^{2} \log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{2 a^{2} b d + 2 b^{3} d} & \text {otherwise} \end {cases} \]
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Time = 0.31 (sec) , antiderivative size = 72, normalized size of antiderivative = 1.09 \[ \int \frac {\tan ^2(c+d x)}{a+b \tan (c+d x)} \, dx=\frac {\frac {2 \, a^{2} \log \left (b \tan \left (d x + c\right ) + a\right )}{a^{2} b + b^{3}} - \frac {2 \, {\left (d x + c\right )} a}{a^{2} + b^{2}} + \frac {b \log \left (\tan \left (d x + c\right )^{2} + 1\right )}{a^{2} + b^{2}}}{2 \, d} \]
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Time = 0.47 (sec) , antiderivative size = 73, normalized size of antiderivative = 1.11 \[ \int \frac {\tan ^2(c+d x)}{a+b \tan (c+d x)} \, dx=\frac {\frac {2 \, a^{2} \log \left ({\left | b \tan \left (d x + c\right ) + a \right |}\right )}{a^{2} b + b^{3}} - \frac {2 \, {\left (d x + c\right )} a}{a^{2} + b^{2}} + \frac {b \log \left (\tan \left (d x + c\right )^{2} + 1\right )}{a^{2} + b^{2}}}{2 \, d} \]
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Time = 5.12 (sec) , antiderivative size = 78, normalized size of antiderivative = 1.18 \[ \int \frac {\tan ^2(c+d x)}{a+b \tan (c+d x)} \, dx=\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )+1{}\mathrm {i}\right )}{2\,d\,\left (b+a\,1{}\mathrm {i}\right )}+\frac {a^2\,\ln \left (a+b\,\mathrm {tan}\left (c+d\,x\right )\right )}{b\,d\,\left (a^2+b^2\right )}+\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )-\mathrm {i}\right )\,1{}\mathrm {i}}{2\,d\,\left (a+b\,1{}\mathrm {i}\right )} \]
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